In 1972, the AP Chemistry exam was designed to assess a student's understanding of college-level introductory chemistry. While modern exams emphasize inquiry-based learning and data analysis, the 1972 exam was more traditional, focusing heavily on rigorous calculations, chemical principles, and descriptive inorganic chemistry.
Moles of M=1.87 g107.9 g/mol≈0.0173 moles of MMoles of cap M equals the fraction with numerator 1.87 g and denominator 107.9 g/mol end-fraction is approximately equal to 0.0173 moles of cap M
These questions required multi-step calculations.
Q=2.50 A×2,700 s=6,750 Ccap Q equals 2.50 A cross 2 comma 700 s equals 6 comma 750 C
Urea (H₂NCONH₂) is produced commercially from the reaction of ammonia and carbon dioxide: 2NH₃(g) + CO₂(g) → H₂NCONH₂(s) + H₂O(g). Ammonia gas at 223°C and 90 atm flows into a reactor at a rate of 500 L/min. Carbon dioxide at 223°C and 45 atm flows into the reactor at a rate of 600 L/min. What mass of urea is produced per minute by this reaction assuming a 74% yield?
In 1972, the AP Chemistry exam was designed to assess a student's understanding of college-level introductory chemistry. While modern exams emphasize inquiry-based learning and data analysis, the 1972 exam was more traditional, focusing heavily on rigorous calculations, chemical principles, and descriptive inorganic chemistry.
Moles of M=1.87 g107.9 g/mol≈0.0173 moles of MMoles of cap M equals the fraction with numerator 1.87 g and denominator 107.9 g/mol end-fraction is approximately equal to 0.0173 moles of cap M
These questions required multi-step calculations.
Q=2.50 A×2,700 s=6,750 Ccap Q equals 2.50 A cross 2 comma 700 s equals 6 comma 750 C
Urea (H₂NCONH₂) is produced commercially from the reaction of ammonia and carbon dioxide: 2NH₃(g) + CO₂(g) → H₂NCONH₂(s) + H₂O(g). Ammonia gas at 223°C and 90 atm flows into a reactor at a rate of 500 L/min. Carbon dioxide at 223°C and 45 atm flows into the reactor at a rate of 600 L/min. What mass of urea is produced per minute by this reaction assuming a 74% yield?